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Electrochemistry question

2020 · 2 Sep · Shift 2 · Q1
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Electrochemistry question

2020 · 2 Sep · Shift 2 · Q1

JEE MainChemistryElectrochemistryNumerical+4 / −1
For the disproportionation reaction 2Cu+Cu^+Cu+(aq) ⇌ CuCuCu(s) + Cu2+Cu^{2+}Cu2+(aq) at 298 K. ln K (where K is the equilibrium constant) is ‾\underline{\hspace{2cm}}​ × 10–1. Given : (ECu2+/Cu+0=0.16VECu+/Cu0=0.52VRTF=0.025E_{C{u^{2 + }}/C{u^ + }}^0 = 0.16VE_{C{u^ + }/Cu}^0 = 0.52V{{RT} \over F} = 0.025ECu2+/Cu+0​=0.16VECu+/Cu0​=0.52VFRT​=0.025)
Numerical answer
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