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Electrochemistry question

2021 · 27 Jul · Shift 2 · Q22

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JEE Main
Chemistry
Electrochemistry
2021 · 27 Jul · Shift 2 · Q22

Electrochemistry question

2021 · 27 Jul · Shift 2 · Q22

JEE MainChemistryElectrochemistryNumerical+4 / −1

For the cell Cu(s) |

Cu^{2+}

(aq) (0.1 M) ||

Ag^+

(aq) (0.01 M) | Ag(s) the cell potential E1 = 0.3095 V For the cell Cu(s) |

Cu^{2+}

(aq) (0.01 M) ||

Ag^+

(aq) (0.001 M) | Ag(s) the cell potential =

\underline{\hspace{2cm}}\times

10

-

2 V. (Round off the nearest integer). [Use :

{{2.303RT} \over F}

= 0.059]

Numerical answer

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