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Electrochemistry question

2020 · 3 Sep · Shift 1 · Q7

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JEE Main
Chemistry
Electrochemistry
2020 · 3 Sep · Shift 1 · Q7

Electrochemistry question

2020 · 3 Sep · Shift 1 · Q7

JEE MainChemistryElectrochemistryNumerical+4 / −1

The photoelectric current from

Na

(Work function, w0 = 2.3 eV) is stopped by the output voltage of the cell Pt(s) |

H_2

(g, 1 Bar) |

HCl

(aq., pH =1) | AgCl(s) | Ag(s). The pH of aq.

HCl

required to stop the photoelectric current form

K

(w0 = 2.25 eV), all other conditions remaining the same, is

\underline{\hspace{2cm}}\times

10-2 (to the nearest integer). Given, 2.303

{{RT} \over F}

= 0.06 V;

E_{AgCl|Ag|C{l^ - }}^0

= 0.22 V

Numerical answer

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