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Electrochemistry question

2021 · 26 Feb · Shift 2 · Q21

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Electrochemistry
2021 · 26 Feb · Shift 2 · Q21

Electrochemistry question

2021 · 26 Feb · Shift 2 · Q21

JEE MainChemistryElectrochemistryNumerical+4 / −1

Emf of the following cell at 298K in V is x

\times

10

-

2.

Zn

|

Zn^{2+}

(0.1 M)||

Ag^+

(0.01 M)|

Ag

The value of x is

\underline{\hspace{2cm}}

. (Rounded off to the nearest integer) [Given :

E_{Z{n^{2 + }}/Zn}^\theta = - 0.76V;E_{A{g^{2 + }}/Ag}^\theta = + 0.80V;{{2.303RT} \over F} = 0.059

]

Numerical answer

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