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D and F Block Elements question

2024 · 27 Jan · Shift 1 · Q20

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Chemistry
D and F Block Elements
2024 · 27 Jan · Shift 1 · Q20

D and F Block Elements question

2024 · 27 Jan · Shift 1 · Q20

JEE MainChemistryD and F Block ElementsMCQ+4 / −1

The electronic configuration for Neodymium is: [Atomic Number for Neodymium 60]

A
$[\mathrm{Xe}] 4 \mathrm{f}^4 6 \mathrm{~s}^2$
B
$[\mathrm{Xe}] 5 \mathrm{f}^4 7 \mathrm{~s}^2$
C
$[\mathrm{Xe}] 4 \mathrm{f}^6 6 \mathrm{~s}^2$
D
$[\mathrm{Xe}] 4 \mathrm{f}^1 5 \mathrm{~d}^1 6 \mathrm{~s}^2$

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