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D and F Block Elements question

2024 · 29 Jan · Shift 1 · Q17
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D and F Block Elements question

2024 · 29 Jan · Shift 1 · Q17

JEE MainChemistryD and F Block ElementsMCQ+4 / −1
KMnO4\mathrm{KMnO}_4KMnO4​ decomposes on heating at 513 K513 \mathrm{~K}513 K to form O2\mathrm{O}_2O2​ along with
  1. A
    K2MnO4 & Mn\mathrm{K}_2 \mathrm{MnO}_4 ~\& \mathrm{~Mn}K2​MnO4​ & Mn
  2. B
    MnO2 & K2O2\mathrm{MnO}_2 ~\& \mathrm{~K}_2 \mathrm{O}_2MnO2​ & K2​O2​
  3. C
    K2MnO4 & MnO2\mathrm{K}_2 \mathrm{MnO}_4 ~\& \mathrm{~MnO}_2K2​MnO4​ & MnO2​
  4. D
    Mn & KO2\mathrm{Mn} ~\& \mathrm{~KO}_2Mn & KO2​
View written solutionFree

Correct answer: C

  1. Recall the thermal decomposition of potassium permanganate

On heating, potassium permanganate decomposes according to the well-known reaction:

2 KMnO4→ΔK2MnO4+MnO2+O22\,\mathrm{KMnO_4} \xrightarrow{\Delta} \mathrm{K_2MnO_4} + \mathrm{MnO_2} + \mathrm{O_2}2KMnO4​Δ​K2​MnO4​+MnO2​+O2​

  1. Check oxidation states to understand the products

In KMnO4\mathrm{KMnO_4}KMnO4​, manganese is in the +7+7+7 oxidation state.

After decomposition:

  • In K2MnO4\mathrm{K_2MnO_4}K2​MnO4​, Mn is +6+6+6
  • In MnO2\mathrm{MnO_2}MnO2​, Mn is +4+4+4
  • Oxygen is released as O2\mathrm{O_2}O2​

So permanganate undergoes simultaneous reduction to manganate and manganese dioxide.

  1. Match with the options

The products formed along with O2\mathrm{O_2}O2​ are:

K2MnO4 and MnO2\mathrm{K_2MnO_4} \text{ and } \mathrm{MnO_2}K2​MnO4​ and MnO2​

Thus, the correct option is:

C: K2MnO4\mathrm{K_2MnO_4}K2​MnO4​ & MnO2\mathrm{MnO_2}MnO2​

  1. Verification with stored answer

Stored correct answer: C

Derived answer: C

They match.

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