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D and F Block Elements question

2024 · 27 Jan · Shift 2 · Q15
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D and F Block Elements question

2024 · 27 Jan · Shift 2 · Q15

JEE MainChemistryD and F Block ElementsMCQ+4 / −1
Choose the correct option having all the elements with d10\mathrm{d}^{10}d10 electronic configuration from the following :
  1. A
    46Pd,28Ni,26Fe,24Cr{ }^{46} \mathrm{Pd},{ }^{28} \mathrm{Ni},{ }^{26} \mathrm{Fe},{ }^{24} \mathrm{Cr}46Pd,28Ni,26Fe,24Cr
  2. B
    29Cu,30Zn,48Cd,47Ag{ }^{29} \mathrm{Cu},{ }^{30} \mathrm{Zn},{ }^{48} \mathrm{Cd},{ }^{47} \mathrm{Ag}29Cu,30Zn,48Cd,47Ag
  3. C
    27Co,28Ni,26Fe,24Cr{ }^{27} \mathrm{Co},{ }^{28} \mathrm{Ni},{ }^{26} \mathrm{Fe},{ }^{24} \mathrm{Cr}27Co,28Ni,26Fe,24Cr
  4. D
    28Ni,24Cr,26Fe,29Cu{ }^{28} \mathrm{Ni},{ }^{24} \mathrm{Cr},{ }^{26} \mathrm{Fe},{ }^{29} \mathrm{Cu}28Ni,24Cr,26Fe,29Cu
View written solutionFree

Correct answer: B

  1. We need the option in which all elements have a d10d^{10}d10 electronic configuration in their atomic ground state.

  2. Let us write the relevant electronic configurations:

  • Cr(Z=24)\mathrm{Cr}(Z=24)Cr(Z=24): [Ar] 3d54s1[Ar] \, 3d^5 4s^1[Ar]3d54s1 So, it is not d10d^{10}d10.

  • Fe(Z=26)\mathrm{Fe}(Z=26)Fe(Z=26): [Ar] 3d64s2[Ar] \, 3d^6 4s^2[Ar]3d64s2 So, it is not d10d^{10}d10.

  • Co(Z=27)\mathrm{Co}(Z=27)Co(Z=27): [Ar] 3d74s2[Ar] \, 3d^7 4s^2[Ar]3d74s2 So, it is not d10d^{10}d10.

  • Ni(Z=28)\mathrm{Ni}(Z=28)Ni(Z=28): [Ar] 3d84s2[Ar] \, 3d^8 4s^2[Ar]3d84s2 So, it is not d10d^{10}d10.

  • Cu(Z=29)\mathrm{Cu}(Z=29)Cu(Z=29): [Ar] 3d104s1[Ar] \, 3d^{10} 4s^1[Ar]3d104s1 So, it has d10d^{10}d10.

  • Zn(Z=30)\mathrm{Zn}(Z=30)Zn(Z=30): [Ar] 3d104s2[Ar] \, 3d^{10} 4s^2[Ar]3d104s2 So, it has d10d^{10}d10.

  • Ag(Z=47)\mathrm{Ag}(Z=47)Ag(Z=47): [Kr] 4d105s1[Kr] \, 4d^{10} 5s^1[Kr]4d105s1 So, it has d10d^{10}d10.

  • Cd(Z=48)\mathrm{Cd}(Z=48)Cd(Z=48): [Kr] 4d105s2[Kr] \, 4d^{10} 5s^2[Kr]4d105s2 So, it has d10d^{10}d10.

  • Pd(Z=46)\mathrm{Pd}(Z=46)Pd(Z=46): [Kr] 4d105s0[Kr] \, 4d^{10} 5s^0[Kr]4d105s0 So, it has d10d^{10}d10.

  1. Now evaluate each option:
  • Option A: Pd,Ni,Fe,Cr\mathrm{Pd}, \mathrm{Ni}, \mathrm{Fe}, \mathrm{Cr}Pd,Ni,Fe,Cr

    • Pd is d10d^{10}d10
    • Ni is not d10d^{10}d10
    • Fe is not d10d^{10}d10
    • Cr is not d10d^{10}d10 Hence, incorrect.
  • Option B: Cu,Zn,Cd,Ag\mathrm{Cu}, \mathrm{Zn}, \mathrm{Cd}, \mathrm{Ag}Cu,Zn,Cd,Ag

    • Cu is d10d^{10}d10
    • Zn is d10d^{10}d10
    • Cd is d10d^{10}d10
    • Ag is d10d^{10}d10 Hence, correct.
  • Option C: Co,Ni,Fe,Cr\mathrm{Co}, \mathrm{Ni}, \mathrm{Fe}, \mathrm{Cr}Co,Ni,Fe,Cr None of these are d10d^{10}d10. Hence, incorrect.

  • Option D: Ni,Cr,Fe,Cu\mathrm{Ni}, \mathrm{Cr}, \mathrm{Fe}, \mathrm{Cu}Ni,Cr,Fe,Cu Only Cu is d10d^{10}d10. Hence, incorrect.

  1. Therefore, the correct option is: B\boxed{B}B​
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