1. Write the ground-state electronic configurations of the given atoms:

• $(A)\ \mathrm{Sc}$ : $[\mathrm{Ar}]\,3d^1 4s^2$
• $(B)\ \mathrm{Cr}$ : $[\mathrm{Ar}]\,3d^5 4s^1$
• $(C)\ \mathrm{V}$ : $[\mathrm{Ar}]\,3d^3 4s^2$
• $(D)\ \mathrm{Ti}$ : $[\mathrm{Ar}]\,3d^2 4s^2$
• $(E)\ \mathrm{Mn}$ : $[\mathrm{Ar}]\,3d^5 4s^2$

2. Count the number of unpaired electrons in each atom:

• Sc: $3d^1$ gives $1$ unpaired electron; $4s^2$ is paired
  $\Rightarrow 1$ unpaired electron

• Ti: $3d^2$ gives $2$ unpaired electrons; $4s^2$ is paired
  $\Rightarrow 2$ unpaired electrons

• V: $3d^3$ gives $3$ unpaired electrons; $4s^2$ is paired
  $\Rightarrow 3$ unpaired electrons

• Cr: $3d^5 4s^1$
  In $3d^5$, all five $d$ orbitals are singly occupied $\Rightarrow 5$ unpaired electrons.
  Also, $4s^1$ contributes $1$ more unpaired electron.
  $\Rightarrow 6$ unpaired electrons

• Mn: $3d^5 4s^2$
  $3d^5$ gives $5$ unpaired electrons; $4s^2$ is paired
  $\Rightarrow 5$ unpaired electrons

3. Arrange in increasing order:

Using the labels:

4. Match with the given options:

This corresponds to Option B.

5. Comparison with stored correct answer:

Stored correct answer = B
Derived answer = B
So, they agree.