Give below are two statements : Statement I : The higher oxidation states are more stable down the group among transition elements unlike p-block elements. Statement II : Copper can not liberate hydrogen from weak acids. In the light of the above statements, choose the correct answer from the options given below :

Both Statement I and Statement II are true

Statement I is true but Statement II is false

Both Statement I and Statement II are false

Statement I is false but Statement II is true

D and F Block Elements PYQ — JEE Main 2024 · 9 Apr · Shift 2 · Q6 with Solution

View written solutionFree

Correct answer: C

Analyze Statement I

Statement I: The higher oxidation states are more stable down the group among transition elements unlike p-block elements.
- In transition elements, especially in the $4d$ and $5d$ series, higher oxidation states become more stable compared to the corresponding $3d$ elements.
- Example:
  - $Fe$ shows a maximum common oxidation state of $+6$ only in strongly oxidizing conditions.
  - $Ru$ and $Os$ show higher oxidation states like $+8$ more readily and stably.
- Thus, down a transition group, higher oxidation states generally become more stable.
For p-block elements, the opposite trend is often observed due to the inert pair effect: lower oxidation states become more stable down the group.

Therefore, Statement I is true.
Analyze Statement II

Statement II: Copper can not liberate hydrogen from weak acids.
- A metal liberates hydrogen from acids only if it is above hydrogen in the electrochemical series.
- Copper lies below hydrogen in the electrochemical series.
- Hence, copper cannot displace hydrogen from dilute non-oxidizing acids, and certainly not from weak acids.
Therefore, Statement II is true.
Choose the correct option
- Statement I: True
- Statement II: True
Hence, the correct option is:

$\boxed{C}$
Comparison with stored answer

Stored correct answer: $C$

My derived answer matches the stored answer.

View written solutionFree

Correct answer: C

Analyze Statement I

Statement I: The higher oxidation states are more stable down the group among transition elements unlike p-block elements.
- In transition elements, especially in the $4d$ and $5d$ series, higher oxidation states become more stable compared to the corresponding $3d$ elements.
- Example:
  - $Fe$ shows a maximum common oxidation state of $+6$ only in strongly oxidizing conditions.
  - $Ru$ and $Os$ show higher oxidation states like $+8$ more readily and stably.
- Thus, down a transition group, higher oxidation states generally become more stable.
For p-block elements, the opposite trend is often observed due to the inert pair effect: lower oxidation states become more stable down the group.

Therefore, Statement I is true.
Analyze Statement II

Statement II: Copper can not liberate hydrogen from weak acids.
- A metal liberates hydrogen from acids only if it is above hydrogen in the electrochemical series.
- Copper lies below hydrogen in the electrochemical series.
- Hence, copper cannot displace hydrogen from dilute non-oxidizing acids, and certainly not from weak acids.
Therefore, Statement II is true.
Choose the correct option
- Statement I: True
- Statement II: True
Hence, the correct option is:

$\boxed{C}$
Comparison with stored answer

Stored correct answer: $C$

My derived answer matches the stored answer.