1. Consider the compound:

$[Ag(NH_3)_2][Ag(CN)_2]$

It contains two different complex ions:

• $[Ag(NH_3)_2]^+$
• $[Ag(CN)_2]^-$

2. Find oxidation state of silver in $[Ag(NH_3)_2]^+$:

• $NH_3$ is a neutral ligand, so its charge is $0$.
• Let oxidation state of Ag be $x$.

Then,

$x + 2(0) = +1$ $x = +1$

So, silver in $[Ag(NH_3)_2]^+$ has oxidation state $+1$.

3. Find oxidation state of silver in $[Ag(CN)_2]^-$:

• $CN^-$ is a ligand with charge $-1$.
• Let oxidation state of Ag be $y$.

Then,

$y + 2(-1) = -1$ $y - 2 = -1$ $y = +1$

So, silver in $[Ag(CN)_2]^-$ also has oxidation state $+1$.

4. Sum of oxidation states of the two silver ions:

$+1 + (+1) = 2$

Therefore, the required integer answer is:

$\boxed{2}$