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Chemical Bonding and Molecular Structure question

2022 · 25 Jul · Shift 2 · Q18

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Chemical Bonding and Molecular Structure
2022 · 25 Jul · Shift 2 · Q18

Chemical Bonding and Molecular Structure question

2022 · 25 Jul · Shift 2 · Q18

JEE MainChemistryChemical Bonding and Molecular StructureNumerical+4 / −1

The sum of number of lone pairs of electrons present on the central atoms of

XeO_3

,

XeOF_4

and

XeF_6

, is

\underline{\hspace{2cm}}

Numerical answer

View written solutionFree

Correct answer: 3

Find lone pairs on the central atom in each molecule

We need the number of lone pairs on the central atom $Xe$ in:

$XeO_3$
$XeOF_4$
$XeF_6$

For $XeO_3$

Xenon has $8$ valence electrons.
In $XeO_3$ , xenon is bonded to $3$ oxygen atoms.
The structure is analogous to $AX_3E$ , where xenon has $3$ bond pairs and $1$ lone pair.

So, lone pairs on central atom in $XeO_3$ : $1$

For $XeOF_4$

Xenon is bonded to $1$ oxygen and $4$ fluorine atoms, so total bonded atoms = $5$ .
The known shape is square pyramidal, corresponding to octahedral electron pair geometry.
Thus it is of type $AX_5E$ .

So, lone pairs on central atom in $XeOF_4$ : $1$

For $XeF_6$

Xenon is bonded to $6$ fluorine atoms.
Total valence electrons of xenon = $8$ .
Six $Xe-F$ bonds use $6$ electron pairs in bonding, and xenon retains $1$ lone pair.
VSEPR description: $AX_6E$ .

So, lone pairs on central atom in $XeF_6$ : $1$

Total lone pairs

$1 + 1 + 1 = 3$

Comparison with stored answer

Stored correct answer = $3$

Our derived answer = $3$

Hence, the answer agrees with the stored correct answer.

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