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Chemical Bonding and Molecular Structure question

2022 · 26 Jul · Shift 1 · Q1
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  5. /2022 · 26 Jul · Shift 1 · Q1

Chemical Bonding and Molecular Structure question

2022 · 26 Jul · Shift 1 · Q1

JEE MainChemistryChemical Bonding and Molecular StructureMCQ+4 / −1

Match List-I with List-II :

List I
(Compound)		 List II
(Shape)
(A) BrF 5_55​ (I) bent
(B) [CrF 6_66​]3−^{3 - }3− (II) square pyramidal
(C) O 3_33​ (III) trigonal bipyramidal
(D) PCl 5_55​ (IV) octahedral

Choose the correct answer from the options given below :

  1. A
    (A)−(I),(B)−(II),(C)−(III),(D)−(IV)(\mathrm{A})-(\mathrm{I}),(\mathrm{B})-(\mathrm{II}),(\mathrm{C})-(\mathrm{III}),(\mathrm{D})-(\mathrm{IV})(A)−(I),(B)−(II),(C)−(III),(D)−(IV)
  2. B
    (A)−(IV),(B)−(III),(C)−(II),(D)−(I)(\mathrm{A})-(\mathrm{IV}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{II}),(\mathrm{D})-(\mathrm{I})(A)−(IV),(B)−(III),(C)−(II),(D)−(I)
  3. C
    (A)−(II),(B)−(IV),(C)−(I),(D)−(III)(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{III})(A)−(II),(B)−(IV),(C)−(I),(D)−(III)
  4. D
    (A)−(III),(B)−(IV),(C)−(II),(D)−(I)(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{II}),(\mathrm{D})-(\mathrm{I})(A)−(III),(B)−(IV),(C)−(II),(D)−(I)
View written solutionFree

Correct answer: C

  1. We determine the shape of each species in List-I.

(A) BrF5\mathrm{BrF_5}BrF5​

  • Central atom: Br
  • Total valence electrons around Br lead to 555 bond pairs and 111 lone pair.
  • Electron pair geometry: octahedral
  • Molecular shape: square pyramidal

So, (A)→(II)(A) \to (II)(A)→(II)

(B) [CrF6]3−[\mathrm{CrF_6}]^{3-}[CrF6​]3−

  • Chromium is surrounded by 666 fluoride ligands.
  • Coordination number =6=6=6
  • The geometry for coordination number 666 here is octahedral.

So, (B)→(IV)(B) \to (IV)(B)→(IV)

(C) O3\mathrm{O_3}O3​

  • Central oxygen has 222 bond pairs and 111 lone pair.
  • Electron pair geometry: trigonal planar
  • Molecular shape: bent

So, (C)→(I)(C) \to (I)(C)→(I)

(D) PCl5\mathrm{PCl_5}PCl5​

  • Central atom: P
  • It has 555 bond pairs and no lone pair.
  • Shape: trigonal bipyramidal

So, (D)→(III)(D) \to (III)(D)→(III)

  1. Final matching:
(A)−(II),(B)−(IV),(C)−(I),(D)−(III)(A)-(II),\quad (B)-(IV),\quad (C)-(I),\quad (D)-(III)(A)−(II),(B)−(IV),(C)−(I),(D)−(III)
  1. Comparing with the options:
  • This corresponds to Option C.
  1. Comparison with stored correct answer:
  • Stored correct answer = C
  • Derived answer = C
  • Hence, they agree.
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