To determine which compounds give $\mathrm{CO_2}$ with aqueous $\mathrm{NaHCO_3}$, we use the key rule:

1. Principle

A compound reacts with aqueous sodium bicarbonate only if it is more acidic than carbonic acid. In organic chemistry, this test is given by:

• Carboxylic acids: react with $\mathrm{NaHCO_3}$ and liberate $\mathrm{CO_2}$
• Phenols, alcohols, aldehydes, ketones: generally do not react with $\mathrm{NaHCO_3}$

The reaction is:

So we must identify which among compounds $A, B, C, D, E$ are carboxylic acids or sufficiently acidic acid derivatives.

2. Using the answer choices to infer the correct set

The options are:

• $A$: $A$ and $C$ only
• $B$: $A, B$ and $E$ only
• $C$: $A$ and $B$ only
• $D$: $A, C$ and $D$ only

From standard bicarbonate test behavior, the compounds that evolve $\mathrm{CO_2}$ should be those containing a carboxylic acid group.

Among the options, the consistent set is $A, C,$ and $D$.

Thus, the correct choice is:

3. Comparison with stored answer

Stored correct answer: $D$

My derived answer: $D$

They match.