Match List - I with List - II.
| List - I | List - II | ||
|---|---|---|---|
| (A) | ![]() | (I) | Etard reaction |
| (B) | ![]() | (II) | Gatterman-Koch reaction |
| (C) | ![]() | (III) | Rosenmund reduction |
| (D) | ![]() | (IV) | Stephen reaction |
Choose the correct answer from the options given below :
- A(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
- B(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
- C(A)-(I), (B)-(III), (C)-(II), (D)-(IV)
- D(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
View written solutionFree
Correct answer: B
We need to match the unnamed entries in List-I with the named reactions in List-II. The standard aldehyde preparation reactions are:
-
Etard reaction
Oxidation of a side-chain methyl group on an aromatic ring to an aldehyde using chromyl chloride.
Example: toluene benzaldehyde. -
Gattermann–Koch reaction
Formylation of benzene or aromatic ring using CO and HCl in presence of to give an aldehyde. -
Rosenmund reduction
Reduction of acid chloride to aldehyde using poisoned Pd catalyst. -
Stephen reaction
Reduction of nitrile with followed by hydrolysis to give aldehyde.
Now compare with the usual reactant/product patterns in List-I:
- Entry corresponding to nitrile aldehyde matches Stephen reaction
- Entry corresponding to acid chloride aldehyde matches Rosenmund reduction
- Entry corresponding to alkyl benzene side-chain oxidation to aldehyde matches Etard reaction
- Entry corresponding to aromatic formylation matches Gattermann–Koch reaction
Thus the correct matching is:
This corresponds to Option B.
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