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Inverse Trigonometric Functions question

2013 · Shift 2 · Q29
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  5. /2013 · Shift 2 · Q29

Inverse Trigonometric Functions question

2013 · Shift 2 · Q29

JEE AdvancedMathematicsInverse Trigonometric FunctionsMCQ+4 / −1
Match List III with List IIIIII and select the correct answer using the code given below the lists: List IP.     IP.\,\,\,\,\,IP. (1y2(cos⁡(tan⁡−1y)+ysin⁡(tan⁡−1y)cot⁡(sin⁡−1y)+tan⁡(sin⁡−1y))2+y4)1/2{\left( {{1 \over {{y^2}}}{{\left( {{{\cos \left( {{{\tan }^{ - 1}}y} \right) + y\sin \left( {{{\tan }^{ - 1}}y} \right)} \over {\cot \left( {{{\sin }^{ - 1}}y} \right) + \tan \left( {{{\sin }^{ - 1}}y} \right)}}} \right)}^2} + {y^4}} \right)^{1/2}}​y21​(cot(sin−1y)+tan(sin−1y)cos(tan−1y)+ysin(tan−1y)​)2+y4​1/2 takes value Q.    Q.\,\,\,\,Q. If cos⁡x+cos⁡y+cos⁡z=0=sin⁡x+sin⁡y+sin⁡z\cos x + \cos y + \cos z = 0 = \sin x + \sin y + \sin zcosx+cosy+cosz=0=sinx+siny+sinz then possible value of cos⁡x−y2\cos {{x - y} \over 2}cos2x−y​ is R.     R.\,\,\,\,\,R. If cos⁡(π4−x)cos⁡2x+sin⁡xsin⁡2sec⁡x=cos⁡xsin⁡2xsec⁡x+cos⁡(π4+x)cos⁡2x\cos \left( {{\pi \over 4} - x} \right)\cos 2x + \sin x\sin 2\sec x = \cos x\sin 2x\sec x + \cos \left( {{\pi \over 4} + x} \right)\cos 2xcos(4π​−x)cos2x+sinxsin2secx=cosxsin2xsecx+cos(4π​+x)cos2x then possible value of sec⁡x\sec xsecx is S.     S.\,\,\,\,\,S. If cot⁡(sin⁡−11−x2)=sin⁡(tan⁡−1(x6)),  xe0,\cot \left( {{{\sin }^{ - 1}}\sqrt {1 - {x^2}} } \right) = \sin \left( {{{\tan }^{ - 1}}\left( {x\sqrt 6 } \right)} \right),\,\,x e 0,cot(sin−11−x2​)=sin(tan−1(x6​)),xe0, Then possible value of xxx is List II1.     12532.     23.     121.    1II1.\,\,\,\,\,{1 \over 2}\sqrt {{5 \over 3}} 2.\,\,\,\,\,\sqrt 2 3.\,\,\,\,\,{1 \over 2}1.\,\,\,\,1II1.21​35​​2.2​3.21​1.1
  1. A
    P=4,Q=3,R=1,S=2P = 4,Q = 3,R = 1,S = 2P=4,Q=3,R=1,S=2
  2. B
    P=4,Q=3,R=2,S=1P = 4,Q = 3,R = 2,S = 1P=4,Q=3,R=2,S=1
  3. C
    P=3,Q=4,R=2,S=1P = 3,Q = 4,R = 2,S = 1P=3,Q=4,R=2,S=1
  4. D
    P=3,Q=4,R=1,S=2P = 3,Q = 4,R = 1,S = 2P=3,Q=4,R=1,S=2
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