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Inverse Trigonometric Functions question

2019 · Shift 2 · Q32
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Inverse Trigonometric Functions question

2019 · Shift 2 · Q32

JEE AdvancedMathematicsInverse Trigonometric FunctionsNumerical+3 / −1
The value of sec⁡−1(14∑k=010sec⁡(7π12+kπ2)sec⁡(7π12+(k+1)π2))\sec^{-1}\left( \frac{1}{4} \sum_{k=0}^{10} \sec\left(\frac{7\pi}{12} + \frac{k\pi}{2}\right) \sec\left(\frac{7\pi}{12} + \frac{(k+1)\pi}{2}\right) \right)sec−1(41​k=0∑10​sec(127π​+2kπ​)sec(127π​+2(k+1)π​)) in the interval [−π4,3π4]\left[-\frac{\pi}{4}, \frac{3\pi}{4}\right][−4π​,43π​] equals ..........
Numerical answer
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