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Inverse Trigonometric Functions question

2008 · Shift 1 · Q33

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PYQ Library
JEE Advanced
Mathematics
Inverse Trigonometric Functions
2008 · Shift 1 · Q33

Inverse Trigonometric Functions question

2008 · Shift 1 · Q33

JEE AdvancedMathematicsInverse Trigonometric FunctionsMCQ+3 / −1

If

0 \lt x \lt 1

, then

\sqrt {1 + {x^2}} {\left[ {{{\left\{ {x\cos \left( {{{\cot }^{ - 1}}x} \right) + \sin \left( {{{\cot }^{ - 1}}x} \right)} \right\}}^2} - 1} \right]^{1/2}} =

A
${x \over {\sqrt {1 + {x^2}} }}$
B
$x$
C
$x\sqrt {1 + {x^2}}$
D
$\sqrt {1 + {x^2}}$

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