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Inverse Trigonometric Functions question

2025 · Shift 2 · Q19
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  5. /2025 · Shift 2 · Q19

Inverse Trigonometric Functions question

2025 · Shift 2 · Q19

JEE AdvancedMathematicsInverse Trigonometric FunctionsMCQ+3 / −1
The total number of real solutions of the equation θ=tan⁡−1(2tan⁡θ)−12sin⁡−1(6tan⁡θ9+tan⁡2θ)\theta = \tan^{-1}(2 \tan \theta) - \frac{1}{2} \sin^{-1}\left(\frac{6 \tan \theta}{9 + \tan^2 \theta}\right)θ=tan−1(2tanθ)−21​sin−1(9+tan2θ6tanθ​) is (Here, the inverse trigonometric functions sin⁡−1x\sin^{-1} xsin−1x and tan⁡−1x\tan^{-1} xtan−1x assume values in [−π2,π2][ -\frac{\pi}{2}, \frac{\pi}{2}][−2π​,2π​] and (−π2,π2)( -\frac{\pi}{2}, \frac{\pi}{2})(−2π​,2π​), respectively.)
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