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Inverse Trigonometric Functions question

2023 · Shift 1 · Q25
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  5. /2023 · Shift 1 · Q25

Inverse Trigonometric Functions question

2023 · Shift 1 · Q25

JEE AdvancedMathematicsInverse Trigonometric FunctionsNumerical+4 / −1
Let tan⁡−1(x)∈(−π2,π2)\tan ^{-1}(x) \in\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)tan−1(x)∈(−2π​,2π​), for x∈Rx \in \mathbb{R}x∈R. Then the number of real solutions of the equation 1+cos⁡(2x)=2tan⁡−1(tan⁡x)\sqrt{1+\cos (2 x)}=\sqrt{2} \tan ^{-1}(\tan x)1+cos(2x)​=2​tan−1(tanx) in the set (−3π2,−π2)∪(−π2,π2)∪(π2,3π2)\left(-\frac{3 \pi}{2},-\frac{\pi}{2}\right) \cup\left(-\frac{\pi}{2}, \frac{\pi}{2}\right) \cup\left(\frac{\pi}{2}, \frac{3 \pi}{2}\right)(−23π​,−2π​)∪(−2π​,2π​)∪(2π​,23π​) is equal to :
Numerical answer
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