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Inverse Trigonometric Functions question

2022 · Shift 1 · Q19
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  5. /2022 · Shift 1 · Q19

Inverse Trigonometric Functions question

2022 · Shift 1 · Q19

JEE AdvancedMathematicsInverse Trigonometric FunctionsNumerical+3 / −1
Considering only the principal values of the inverse trigonometric functions, the value of 32cos⁡−122+π2+14sin⁡−122π2+π2+tan⁡−12π\frac{3}{2} \cos ^{-1} \sqrt{\frac{2}{2+\pi^{2}}}+\frac{1}{4} \sin ^{-1} \frac{2 \sqrt{2} \pi}{2+\pi^{2}}+\tan ^{-1} \frac{\sqrt{2}}{\pi}23​cos−12+π22​​+41​sin−12+π222​π​+tan−1π2​​ is
Numerical answer
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