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Chemical Kinetics and Nuclear Chemistry question

2014 · Shift 2 · Q1
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Chemical Kinetics and Nuclear Chemistry question

2014 · Shift 2 · Q1

JEE AdvancedChemistryChemical Kinetics and Nuclear ChemistryMCQ+3 / −1
For the elementary reaction M →\to→ N, the rate of disappearance of M increases by a factor of 8 upon doubling the concentration of M. The order of the reaction with respect to M is
  1. A
    4
  2. B
    3
  3. C
    2
  4. D
    1
View written solutionFree

Correct answer: B

Step-by-step Derivation:

  1. Define the Rate Law: Let the order of the reaction with respect to the reactant M be 'n'. The rate law for the reaction can be expressed as: Rate=k[M]n\text{Rate} = k[\text{M}]^nRate=k[M]n where Rate is the rate of the reaction, k is the rate constant, and [M] is the concentration of M. The rate of disappearance of M is directly proportional to the rate of the reaction, so we can use this expression.

  2. Set up Initial Conditions: Let the initial rate of disappearance of M be R1R_1R1​ when the concentration of M is [M]1[\text{M}]_1[M]1​. According to the rate law: R1=k[M]1nR_1 = k[\text{M}]_1^nR1​=k[M]1n​

  3. Set up Final Conditions: The problem states that the concentration of M is doubled. So, the new concentration, [M]2[\text{M}]_2[M]2​, is: [M]2=2[M]1[\text{M}]_2 = 2[\text{M}]_1[M]2​=2[M]1​ Upon doubling the concentration, the rate of disappearance of M increases by a factor of 8. So, the new rate, R2R_2R2​, is: R2=8R1R_2 = 8R_1R2​=8R1​ The new rate can also be expressed using the rate law with the new concentration: R2=k[M]2nR_2 = k[\text{M}]_2^nR2​=k[M]2n​

  4. Solve for the Order (n): Now we have a system of two equations: (i) R1=k[M]1nR_1 = k[\text{M}]_1^nR1​=k[M]1n​ (ii) R2=k[M]2nR_2 = k[\text{M}]_2^nR2​=k[M]2n​

    Substitute the given relationships into equation (ii): 8R1=k(2[M]1)n8R_1 = k(2[\text{M}]_1)^n8R1​=k(2[M]1​)n

    Divide the modified equation (ii) by equation (i): 8R1R1=k(2[M]1)nk[M]1n\frac{8R_1}{R_1} = \frac{k(2[\text{M}]_1)^n}{k[\text{M}]_1^n}R1​8R1​​=k[M]1n​k(2[M]1​)n​

    Simplify the expression: 8=2n[M]1n[M]1n8 = \frac{2^n [\text{M}]_1^n}{[\text{M}]_1^n}8=[M]1n​2n[M]1n​​ 8=2n8 = 2^n8=2n

    To find the value of n, we can express 8 as a power of 2: 23=2n2^3 = 2^n23=2n

    Therefore, the order of the reaction with respect to M is: n=3n = 3n=3

  5. Conclusion: The order of the reaction with respect to M is 3. This corresponds to option B.

    Note: The question describes the reaction M →\to→ N as "elementary". For an elementary reaction, the order is typically equal to the stoichiometric coefficient of the reactant, which is 1 in this case. However, the experimental data provided (rate increases 8-fold when concentration doubles) leads to an order of 3. In chemical kinetics, the order of a reaction is an experimentally determined quantity. When experimental data contradicts the stoichiometry of a supposedly elementary reaction, the experimental data is used to determine the rate law. Therefore, we base our answer on the given rate change.

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