- A4
- B3
- C2
- D1
View written solutionFree
Correct answer: B
Step-by-step Derivation:
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Define the Rate Law: Let the order of the reaction with respect to the reactant M be 'n'. The rate law for the reaction can be expressed as: where
Rateis the rate of the reaction,kis the rate constant, and[M]is the concentration of M. The rate of disappearance of M is directly proportional to the rate of the reaction, so we can use this expression. -
Set up Initial Conditions: Let the initial rate of disappearance of M be when the concentration of M is . According to the rate law:
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Set up Final Conditions: The problem states that the concentration of M is doubled. So, the new concentration, , is: Upon doubling the concentration, the rate of disappearance of M increases by a factor of 8. So, the new rate, , is: The new rate can also be expressed using the rate law with the new concentration:
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Solve for the Order (n): Now we have a system of two equations: (i) (ii)
Substitute the given relationships into equation (ii):
Divide the modified equation (ii) by equation (i):
Simplify the expression:
To find the value of n, we can express 8 as a power of 2:
Therefore, the order of the reaction with respect to M is:
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Conclusion: The order of the reaction with respect to M is 3. This corresponds to option B.
Note: The question describes the reaction M N as "elementary". For an elementary reaction, the order is typically equal to the stoichiometric coefficient of the reactant, which is 1 in this case. However, the experimental data provided (rate increases 8-fold when concentration doubles) leads to an order of 3. In chemical kinetics, the order of a reaction is an experimentally determined quantity. When experimental data contradicts the stoichiometry of a supposedly elementary reaction, the experimental data is used to determine the rate law. Therefore, we base our answer on the given rate change.
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