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Chemical Kinetics and Nuclear Chemistry question

2012 · Shift 1 · Q1

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JEE Advanced
Chemistry
Chemical Kinetics and Nuclear Chemistry
2012 · Shift 1 · Q1

Chemical Kinetics and Nuclear Chemistry question

2012 · Shift 1 · Q1

JEE AdvancedChemistryChemical Kinetics and Nuclear ChemistryNumerical+3 / −1

An organic compound undergoes first-order decomposition. The time taken for its decomposition to 1/8 and 1/10 of its initial concentration are t1/8 and t1/10 respectively. What is the value of

\left[ {{{{t_{1/8}}} \over {{t_{1/10}}}}} \right] \times 10

? (

{\log _{10}}2 = 0.3

)

Numerical answer

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