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Wave Optics question

2016 · Q134
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Wave Optics question

2016 · Q134

NEETPhysicsWave OpticsMCQ+4 / −1
A linear aperture whose width is 0.02 cm is placed immediately in front of a lens of focal length 60 cm. The aparture is illuminated normally by a parallel beam of wavelength 5 ×\times× 10−-−5 cm. The distance of the first dark band of the diffraction pattern from the centre of the screen is
  1. A
    0.10 cm
  2. B
    0.25 cm
  3. C
    0.20 cm
  4. D
    0.15 cm
View written solutionFree

Correct answer: D

Here, a = 0.02 cm = 2 × 10–4 m

λ\lambda λ = 5 × 10–5 cm = 5 × 10–7 m

D = 60 cm = 0.6 m

Position of first minima on the diffraction pattern,

y1 = Dλa{{D\lambda } \over a}aDλ​

= 0.6×5×10−72×10−4{{0.6 \times 5 \times {{10}^{ - 7}}} \over {2 \times {{10}^{ - 4}}}}2×10−40.6×5×10−7​ = 15 ×\times× 10-4 m = 0.15 cm

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