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Wave Optics question

2013 · Q133
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Wave Optics question

2013 · Q133

NEETPhysicsWave OpticsMCQ+4 / −1
In Young's double slit experiment the distance between the slits and the screen is doubled. The separation between the slits is reduced to half. As a result the fringe width
  1. A
    is halved
  2. B
    becomes four times
  3. C
    remains unchanged
  4. D
    is doubled
View written solutionFree

Correct answer: B

Fringe width, β\beta β = λDd{{\lambda D} \over d}dλD​

From question D' = 2D and d' = d2{d \over 2}2d​

∴\therefore∴ β\beta β' = λD′d′{{\lambda D'} \over {d'}}d′λD′​ = 4β\beta β

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