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Wave Optics question

2013 · Q135
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Wave Optics question

2013 · Q135

NEETPhysicsWave OpticsMCQ+4 / −1
A parallel beam of light of wavelength λ\lambdaλ is incident normally on a narrow slit. A diffraction pattern formed on a screen placed perpenficular to the direction of the incident beam. At the second minimum of the diffraction pattern, the phase difference between the rays coming from the two edges of slit is
  1. A
    2π\piπ
  2. B
    3π\piπ
  3. C
    4π\piπ
  4. D
    π\piπλ\lambdaλ
View written solutionFree

Correct answer: C

\Delta $$\phi = 2πλ×{{2\pi } \over \lambda } \times λ2π​× Path Difference

= 2πλ×2λ{{2\pi } \over \lambda } \times 2\lambda λ2π​×2λ = 4π\pi π

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