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Wave Optics question

2015 · Q121
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Wave Optics question

2015 · Q121

NEETPhysicsWave OpticsMCQ+4 / −1
At the first minimum adjacent to the central maximum of a single-slit diffraction pattern, the phase difference between the Huygen's wavelet from the edge of the slit and the wavelet from the midpoint of the slit is
  1. A
    π\piπ radian
  2. B
    π8{\pi \over 8}8π​ radian
  3. C
    π4{\pi \over 4}4π​ radian
  4. D
    π2{\pi \over 2}2π​ radian
View written solutionFree

Correct answer: A

AIPMT 2015 Physics - Wave Optics Question 31 English Explanation


For first minima at P

AP – BP = $\lambda $

AP – MP = ${\lambda \over 2}$

So phase difference, $\phi $ = $${{2\pi } \over \lambda } \times {\lambda \over 2}$$ = $\pi $ radian
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