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Wave Optics question

2015 · Q125
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Wave Optics question

2015 · Q125

NEETPhysicsWave OpticsMCQ+4 / −1
For a parallel beam of monochromatic light of wavelength 'λ\lambdaλ' , diffraction is produced by a single slit whose width 'a' is of the order of the wavelength of the light. If 'D' is the distance of the screen from the slit, the wifth of the central maxima will be
  1. A
    Daλ{{Da} \over \lambda }λDa​
  2. B
    2Daλ{{2Da} \over \lambda }λ2Da​
  3. C
    2Dλa{{2D\lambda } \over a}a2Dλ​
  4. D
    Dλa{{D\lambda } \over a}aDλ​
View written solutionFree

Correct answer: C

AIPMT 2015 Cancelled Paper Physics - Wave Optics Question 29 English Explanation


For central maxima, sin $\theta $ = ${\lambda \over a}$

Also, $\theta $ is very-very small so

sin $\theta $ $ \approx $ tan$\theta $ = ${y \over D}$

$ \therefore $ ${y \over D}$ = ${\lambda \over a}$

$ \Rightarrow $ y = $${{\lambda D} \over a}$$

Width of central maxima = 2y = $${{2D\lambda } \over a}$$
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