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Wave Optics question

2015 · Q127
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Wave Optics question

2015 · Q127

NEETPhysicsWave OpticsMCQ+4 / −1
In a double slit experiment, the two slits are 1 mm apart and the screen is placed 1 m away. A monochromatic light of wavelength 500 nm is used. What will be the width of each slit for obtaining ten maxima of double slit within the central maxima of single slit pattern ?
  1. A
    0.5 mm
  2. B
    0.02 mm
  3. C
    0.2 mm
  4. D
    0.1 mm
View written solutionFree

Correct answer: C

Fringe width, β\beta β = Dλd{{D\lambda } \over d}dDλ​

As per question, width of central maxima of single slit pattern = width of 10 maxima of double slit pattern

D2λa=10(λDd){{D2\lambda } \over a} = 10\left( {{{\lambda D} \over d}} \right)aD2λ​=10(dλD​)

⇒\Rightarrow⇒ aaa = 2d10{{2d} \over {10}}102d​ = 2×10−310{{2 \times {{10}^{ - 3}}} \over {10}}102×10−3​ = 0.2 ×\times× 10-3 m = 0.2 mm

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