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Moving Charges and Magnetism question

2013 · Q128
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Moving Charges and Magnetism question

2013 · Q128

NEETPhysicsMoving Charges and MagnetismMCQ+4 / −1
A circular coil ABCD carrying a current 'i' is placed in a uniform magnetic field. If the magnetic force on the segment AB is F→\overrightarrow FF, the force on the remaining segment BCDA is

NEET 2013 (Karnataka) Physics - Moving Charges and Magnetism Question 63 English
  1. A
    −F→- \overrightarrow F−F
  2. B
    3F→3\overrightarrow F3F
  3. C
    −-−3F→3\overrightarrow F3F
  4. D
    F→\overrightarrow FF
View written solutionFree

Correct answer: A

Here, F→AB+F→BCDA=0→{\overrightarrow F _{AB}} + {\overrightarrow F _{BCDA}} = \overrightarrow 0 FAB​+FBCDA​=0

⇒F→BCDA=−F→AB=−F→\Rightarrow {\overrightarrow F _{BCDA}} = - {\overrightarrow F _{AB}} = - \overrightarrow F⇒FBCDA​=−FAB​=−F

   (∵\because∵ FAB = F→\overrightarrow F F)

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