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Moving Charges and Magnetism question

2013 · Q127
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Moving Charges and Magnetism question

2013 · Q127

NEETPhysicsMoving Charges and MagnetismMCQ+4 / −1
A long straight wire carries a certain current and produces a magnetic field 2 ×\times× 10−-−4 Wb m−-−2 at a perpendicular distance of 5 cm from the wire. An electron situated at 5 cm from the wire moves with a velocity 107 m/s towards the wire along perpendicular to it. The force experienced by the electron will be (charge on electron 1.6 ×\times× 10−-−19 C)
  1. A
    3.2 N
  2. B
    3.2 ×\times× 10−-−16 N
  3. C
    1.6 ×\times× 10−-−16 N
  4. D
    zero
View written solutionFree

Correct answer: B

The situation is as shown in the figure.

NEET 2013 (Karnataka) Physics - Moving Charges and Magnetism Question 64 English Explanation

Here, v = 107 m/s, B = 2 × 10–4 Wb/m2

The magnitude of the force experienced by the electron is

F = evBsinθ\theta θ

   (∵v→ and B→ are\because {\overrightarrow v \,and\,\overrightarrow B \,are}∵vandBare perpendicular to each other)

= evBsin90° = 1.6 × 10–19 × 107 × 2 × 10–4 × 1

= 3.2 × 10–16 N

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