NEETPhysicsAlternating CurrentMCQ+4 / −1
A capacitor is connected to a source as shown in figure. The peak current in the circuit is nearly :

- A0.58 A
- B0.93 A
- C1.20 A
- D0.35 A
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Correct answer: B
Capacitive Reactance
$$\begin{aligned} X_C =\frac{1}{\omega C}=\frac{1}{2 \pi f C}=\frac{1}{2 \times 3.14 \times 50 \times 10 \times 10^{-6}} \\ =\frac{1000}{3.14}\end{aligned}$$
$$ \begin{aligned} & V_{\mathrm{rms}}=210 \mathrm{~V} \\ & i_{\mathrm{rms}}=\frac{V_{\mathrm{rms}}}{X_C}=\frac{210}{X_C} \\ & \text { Peak current }=\sqrt{2} i_{\mathrm{ms}}=\sqrt{2} \times \frac{210}{1000} \times 3.14=0.932 \\ & \qquad =0.93 \mathrm{~A} \end{aligned} $$
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