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Alternating Current question

2024 · Q199
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Alternating Current question

2024 · Q199

NEETPhysicsAlternating CurrentMCQ+4 / −1

The amplitude of the charge oscillating in a circuit decreases exponentially as Q=Q0e−Rt/2LQ=Q_0 e^{-R t/2 L}Q=Q0​e−Rt/2L, where Q0Q_0Q0​ is the charge at t=0 st=0 \mathrm{~s}t=0 s. The time at which charge amplitude decreases to 0.50Q00.50 Q_00.50Q0​ is nearly:

[Given that R=1.5Ω,L=12 mH,ln⁡(2)=0.693R=1.5 \Omega, L=12 \mathrm{~mH}, \ln (2)=0.693R=1.5Ω,L=12 mH,ln(2)=0.693]

  1. A
    19.01 ms
  2. B
    11.09 ms
  3. C
    19.01 s
  4. D
    11.09 s
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