NEETPhysicsAlternating CurrentMCQ+4 / −1
For very high frequencies, the effective impedance of the circuit (shown in the figure) will be:-

- A4
- B6
- C1
- D3
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Correct answer: D
As frequency is very high
$$\mathrm{X_C \approx 0}$$
$$\mathrm{X_L\to\alpha}$$
Effective circuit will be

Effective impedance of circuit will be = 3$\Omega$
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