1. Given data

• Mass of block: $m = 5\,\text{kg}$
• Amplitude: $A = 1\,\text{m}$
• Time period: $T = 3.14\,\text{s}$

We need the maximum spring force.

2. Formula for maximum spring force in SHM

For a spring-block system,

$F = -kx$

So the maximum force occurs at maximum displacement $x = A$:

$F_{\max} = kA$

Thus we first find the spring constant $k$.

3. Use time period formula

For a mass-spring system,

$T = 2\pi \sqrt{\frac{m}{k}}$

Rearranging,

$k = \frac{4\pi^2 m}{T^2}$

Substitute the values:

$k = \frac{4\pi^2 \cdot 5}{(3.14)^2}$

Since $3.14 \approx \pi$,

$T \approx \pi$

So,

$k = \frac{4\pi^2 \cdot 5}{\pi^2} = 20\,\text{N/m}$

4. Find maximum force

$F_{\max} = kA = 20 \times 1 = 20\,\text{N}$

5. Final answer

$\boxed{20}$