JEE MainPhysicsSimple Harmonic MotionNumerical+4 / −1
A block of a mass 2 kg is attached with two identical springs of spring constant 20 N/m each. The block is placed on a frictionless surface and the ends of the springs are attached to rigid supports (see figure). When the mass is displaced from its equilibrium position, it executes a simple harmonic motion. The time period of oscillation is in SI unit. The value of is .Numerical answer
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Correct answer: 5
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Identify the effective spring constant
The block is attached to two identical springs, each of spring constant
When the block is displaced by a distance , one spring gets compressed and the other gets stretched by the same amount.
Each spring exerts a restoring force of magnitude
So the total restoring force on the block is
Hence, the effective spring constant is
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Use the time period formula for SHM
For a mass-spring system,
Here,
Therefore,
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Compare with the given form
Given,
Comparing with we get
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Comparison with stored answer
Stored correct answer:
Our derived answer matches the stored answer.
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