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Simple Harmonic Motion question

2023 · 8 Apr · Shift 2 · Q44
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  5. /2023 · 8 Apr · Shift 2 · Q44

Simple Harmonic Motion question

2023 · 8 Apr · Shift 2 · Q44

JEE MainPhysicsSimple Harmonic MotionMCQ+4 / −1
For particle P revolving round the centre O with radius of circular path r\mathrm{r}r and angular velocity ω\omegaω, as shown in below figure, the projection of OP on the xxx-axis at time ttt is JEE Main 2023 (Online) 8th April Evening Shift Physics - Simple Harmonic Motion Question 29 English
  1. A
    x(t)=cos⁡(ωt−π6ω)x(t)=\operatorname{cos}\left(\omega t-\frac{\pi}{6} \omega\right)x(t)=cos(ωt−6π​ω)
  2. B
    x(t)=cos⁡(ωt)x(t)=\operatorname{cos}(\omega t)x(t)=cos(ωt)
  3. C
    x(t)=rcos⁡(ωt+π6)x(t)=r \cos \left(\omega t+\frac{\pi}{6}\right)x(t)=rcos(ωt+6π​)
  4. D
    x(t)=rsin⁡(ωt+π6)x(t)=r \sin \left(\omega t+\frac{\pi}{6}\right)x(t)=rsin(ωt+6π​)
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