- ABoth Statement I and Statement II are true
- BBoth Statement I and Statement II are false
- CStatement I is true but Statement II is false.
- DStatement I is false but Statement II is true.
View written solutionFree
Correct answer: C
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Interpret Statement I
For a gas in thermal equilibrium, molecular energies are statistically distributed.
- Translational speeds follow the Maxwell distribution.
- Rotational degrees of freedom of molecules in thermal equilibrium also have a thermal distribution governed by Boltzmann statistics.
For a diatomic molecule, rotational motion contributes energy, and over a large ensemble the rotational energies are distributed statistically at a given temperature.
Hence, Statement I is taken as true.
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Interpret Statement II
Statement II says:
In a diatomic molecule, the rotational energy at a given temperature equals the translational kinetic energy for each molecule.
This is incorrect.
By the equipartition theorem:
- Average translational kinetic energy per molecule:
- Average rotational energy per diatomic molecule (ignoring vibration, with 2 active rotational degrees):
These are not equal, even on average.
Also, the statement says "for each molecule," which is even more wrong, because individual molecules do not all have the same energy.
So, Statement II is false.
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Choose the correct option
- Statement I: True
- Statement II: False
Therefore, the correct option is:
-
Compare with stored answer
Stored correct answer: C
My derived answer matches the stored answer.
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