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Current Electricity question

2024 · 5 Apr · Shift 2 · Q78
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  5. /2024 · 5 Apr · Shift 2 · Q78

Current Electricity question

2024 · 5 Apr · Shift 2 · Q78

JEE MainPhysicsCurrent ElectricityMCQ+4 / −1
A galvanometer of resistance 100Ω100 \Omega100Ω when connected in series with 400Ω400 \Omega400Ω measures a voltage of upto 10 V10 \mathrm{~V}10 V. The value of resistance required to convert the galvanometer into ammeter to read upto 10 A10 \mathrm{~A}10 A is x×10−2Ωx \times 10^{-2} \Omegax×10−2Ω. The value of xxx is :
  1. A
    2
  2. B
    20
  3. C
    800
  4. D
    200
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