1. Use the linear temperature dependence of resistance

For a metallic wire, resistance varies as

$R_t = R_0(1+\alpha t)$

where:

• $R_0$ is resistance at $0^\circ\text{C}$
• $\alpha$ is temperature coefficient at $0^\circ\text{C}$
• $t$ is in $^\circ\text{C}$

Given:

$R_0 = 10\,\Omega$ $R_{100} = 10.2\,\Omega$ $R_t = 10.95\,\Omega$

2. Find $\alpha$ using the value at $100^\circ\text{C}$

Using

$R_{100} = R_0(1+100\alpha)$

Substitute values:

$10.2 = 10(1+100\alpha)$

Divide by 10:

$1.02 = 1+100\alpha$

So,

$100\alpha = 0.02$ $\alpha = 0.0002 = 2\times 10^{-4}\, ^\circ\text{C}^{-1}$

3. Use resistance at $t^\circ\text{C}$ to find $t$

$R_t = R_0(1+\alpha t)$

So,

$10.95 = 10(1+0.0002t)$

Divide by 10:

$1.095 = 1+0.0002t$

Hence,

$0.0002t = 0.095$

$t = \frac{0.095}{0.0002} = 475^\circ\text{C}$

4. Convert to Kelvin

$T = 475 + 273 = 748\,\text{K}$

5. Final Answer

The temperature in Kelvin scale is

$\boxed{748}$