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Current Electricity question

2024 · 5 Apr · Shift 1 · Q85
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  5. /2024 · 5 Apr · Shift 1 · Q85

Current Electricity question

2024 · 5 Apr · Shift 1 · Q85

JEE MainPhysicsCurrent ElectricityNumerical+4 / −1
In the experiment to determine the galvanometer resistance by half-deflection method, the plot of 1/θ1 / \theta1/θ vs the resistance (R) of the resistance box is shown in the figure. The figure of merit of the galvanometer is ‾\underline{\hspace{2cm}}​×10−1 A/\times 10^{-1} \mathrm{~A} /×10−1 A/ division. [The source has emf 2 V2 \mathrm{~V}2 V] JEE Main 2024 (Online) 5th April Morning Shift Physics - Current Electricity Question 30 English
Numerical answer
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