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Vector Algebra question

2021 · 27 Aug · Shift 1 · Q34
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  5. /2021 · 27 Aug · Shift 1 · Q34

Vector Algebra question

2021 · 27 Aug · Shift 1 · Q34

JEE MainMathematicsVector AlgebraNumerical+4 / −1
Let a→=i^+5j^+αk^\overrightarrow a = \widehat i + 5\widehat j + \alpha \widehat ka=i+5j​+αk, b→=i^+3j^+βk^\overrightarrow b = \widehat i + 3\widehat j + \beta \widehat kb=i+3j​+βk and c→=−i^+2j^−3k^\overrightarrow c = - \widehat i + 2\widehat j - 3\widehat kc=−i+2j​−3k be three vectors such that, ∣b→×c→∣=53\left| {\overrightarrow b \times \overrightarrow c } \right| = 5\sqrt 3​b×c​=53​ and a→{\overrightarrow a }a is perpendicular to b→{\overrightarrow b }b. Then the greatest amongst the values of ∣a→∣2{\left| {\overrightarrow a } \right|^2}​a​2 is ‾\underline{\hspace{2cm}}​.
Numerical answer
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