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Probability question

2009 · Shift 0 · Q32
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  5. /2009 · Shift 0 · Q32

Probability question

2009 · Shift 0 · Q32

JEE MainMathematicsProbabilityMCQ+4 / −1
One ticket is selected at random from 505050 tickets numbered 00,01,02,....,49.00, 01, 02, ...., 49.00,01,02,....,49. Then the probability that the sum of the digits on the selected ticket is 888, given that the product of these digits is zer, equals :
  1. A
    17{1 \over 7}71​
  2. B
    514{5 \over 14}145​
  3. C
    150{1 \over 50}501​
  4. D
    114{1 \over 14}141​
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