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Probability question

2008 · Shift 0 · Q34
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  5. /2008 · Shift 0 · Q34

Probability question

2008 · Shift 0 · Q34

JEE MainMathematicsProbabilityMCQ+4 / −1
It is given that the events AAA and BBB are such that P(A)=14,P(A∣B)=12P\left( A \right) = {1 \over 4},P\left( {A|B} \right) = {1 \over 2}P(A)=41​,P(A∣B)=21​ and P(B∣A)=23.P\left( {B|A} \right) = {2 \over 3}.P(B∣A)=32​. Then P(B)P(B)P(B) is :
  1. A
    16{1 \over 6}61​
  2. B
    13{1 \over 3}31​
  3. C
    23{2 \over 3}32​
  4. D
    12{1 \over 2}21​
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