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Limits Continuity and Differentiability question

2022 · 28 Jul · Shift 2 · Q25
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  5. /2022 · 28 Jul · Shift 2 · Q25

Limits Continuity and Differentiability question

2022 · 28 Jul · Shift 2 · Q25

JEE MainMathematicsLimits Continuity and DifferentiabilityMCQ+4 / −1
The function f:R→Rf: \mathbb{R} \rightarrow \mathbb{R}f:R→R defined by f(x)=lim⁡n→∞cos⁡(2πx)−x2nsin⁡(x−1)1+x2n+1−x2nf(x)=\lim\limits_{n \rightarrow \infty} \frac{\cos (2 \pi x)-x^{2 n} \sin (x-1)}{1+x^{2 n+1}-x^{2 n}}f(x)=n→∞lim​1+x2n+1−x2ncos(2πx)−x2nsin(x−1)​ is continuous for all x in :
  1. A
    R−{−1}R-\{-1\}R−{−1}
  2. B
    R−{−1,1}\mathbb{R}-\{-1,1\}R−{−1,1}
  3. C
    R−{1}R-\{1\}R−{1}
  4. D
    R−{0}R-\{0\}R−{0}
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