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Limits Continuity and Differentiability question

2022 · 28 Jun · Shift 2 · Q44
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  5. /2022 · 28 Jun · Shift 2 · Q44

Limits Continuity and Differentiability question

2022 · 28 Jun · Shift 2 · Q44

JEE MainMathematicsLimits Continuity and DifferentiabilityNumerical+4 / −1
If lim⁡x→1sin⁡(3x2−4x+1)−x2+12x3−7x2+ax+b=−2\mathop {\lim }\limits_{x \to 1} {{\sin (3{x^2} - 4x + 1) - {x^2} + 1} \over {2{x^3} - 7{x^2} + ax + b}} = - 2x→1lim​2x3−7x2+ax+bsin(3x2−4x+1)−x2+1​=−2, then the value of (a −-− b) is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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