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Limits Continuity and Differentiability question

2022 · 28 Jul · Shift 1 · Q45

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JEE Main
Mathematics
Limits Continuity and Differentiability
2022 · 28 Jul · Shift 1 · Q45

Limits Continuity and Differentiability question

2022 · 28 Jul · Shift 1 · Q45

JEE MainMathematicsLimits Continuity and DifferentiabilityNumerical+4 / −1

\lim\limits_{x \rightarrow 0}\left(\frac{(x+2 \cos x)^{3}+2(x+2 \cos x)^{2}+3 \sin (x+2 \cos x)}{(x+2)^{3}+2(x+2)^{2}+3 \sin (x+2)}\right)^{\frac{100}{x}}

is equal to

\underline{\hspace{2cm}}

.

Numerical answer

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