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Limits Continuity and Differentiability question

2022 · 28 Jun · Shift 2 · Q38
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  5. /2022 · 28 Jun · Shift 2 · Q38

Limits Continuity and Differentiability question

2022 · 28 Jun · Shift 2 · Q38

JEE MainMathematicsLimits Continuity and DifferentiabilityMCQ+4 / −1
The value of lim⁡n→∞6tan⁡{∑r=1ntan⁡−1(1r2+3r+3)}\mathop {\lim }\limits_{n \to \infty } 6\tan \left\{ {\sum\limits_{r = 1}^n {{{\tan }^{ - 1}}\left( {{1 \over {{r^2} + 3r + 3}}} \right)} } \right\}n→∞lim​6tan{r=1∑n​tan−1(r2+3r+31​)} is equal to :
  1. A
    1
  2. B
    2
  3. C
    3
  4. D
    6
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