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Limits Continuity and Differentiability question

2022 · 28 Jul · Shift 1 · Q40
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Limits Continuity and Differentiability question

2022 · 28 Jul · Shift 1 · Q40

JEE MainMathematicsLimits Continuity and DifferentiabilityNumerical+4 / −1
Let f:[0,1]→Rf:[0,1] \rightarrow \mathbf{R}f:[0,1]→R be a twice differentiable function in (0,1)(0,1)(0,1) such that f(0)=3f(0)=3f(0)=3 and f(1)=5f(1)=5f(1)=5. If the line y=2x+3y=2 x+3y=2x+3 intersects the graph of fff at only two distinct points in (0,1)(0,1)(0,1), then the least number of points x∈(0,1)x \in(0,1)x∈(0,1), at which f′′(x)=0f^{\prime \prime}(x)=0f′′(x)=0, is ‾\underline{\hspace{2cm}}​.
Numerical answer
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