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Limits Continuity and Differentiability question

2022 · 24 Jun · Shift 1 · Q39
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  5. /2022 · 24 Jun · Shift 1 · Q39

Limits Continuity and Differentiability question

2022 · 24 Jun · Shift 1 · Q39

JEE MainMathematicsLimits Continuity and DifferentiabilityNumerical+4 / −1
The number of points where the function f(x)={∣2x2−3x−7∣ifx≤−1[4x2−1]if−1<x<1∣x+1∣+∣x−2∣ifx≥1f(x) = \left\{ \begin{array}{lcl} |2x^2 - 3x - 7| & \text{if} & x \le -1 \\ [4x^2 - 1] & \text{if} & -1 \lt x \lt 1 \\ |x + 1| + |x - 2| & \text{if} & x \ge 1 \end{array} \right.f(x)=⎩⎨⎧​∣2x2−3x−7∣[4x2−1]∣x+1∣+∣x−2∣​ififif​x≤−1−1<x<1x≥1​ where [t][t][t] denotes the greatest integer ≤t\le t≤t, is discontinuous is ‾\underline{\hspace{2cm}}​.
Numerical answer
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