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Limits Continuity and Differentiability question

2018 · 15 Apr · Shift 2 · Q44
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  5. /2018 · 15 Apr · Shift 2 · Q44

Limits Continuity and Differentiability question

2018 · 15 Apr · Shift 2 · Q44

JEE MainMathematicsLimits Continuity and DifferentiabilityMCQ+4 / −1
lim⁡x→0xtan⁡2x−2xtan⁡x(1−cos⁡2x)2\mathop {\lim }\limits_{x \to 0} {{x\tan 2x - 2x\tan x} \over {{{\left( {1 - \cos 2x} \right)}^2}}}x→0lim​(1−cos2x)2xtan2x−2xtanx​ equals :
  1. A
    14{1 \over 4}41​
  2. B
    1
  3. C
    12{1 \over 2}21​
  4. D
    −12-{1 \over 2}−21​
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